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Old Oct 3rd 2016, 06:40 AM   #1
Jrt
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Arrow A level help

Hiya
Was wandering if anyone could explain the following:
n+ p - k+ x
Deduce the relative charge, baryon number and strangeness of particle x ?
Thanks
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Old Oct 3rd 2016, 01:16 PM   #2
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That makes no sense. Where did you find that expression? Was it part of an equation? What do "n", "p", "k", and "x" mean? You also ask about "particle x". Since the first expression involved adding and subtraction, I assumed that "n", "p", "k", and "x" were numbers. How did x become a particle?
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Old Oct 3rd 2016, 04:35 PM   #3
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I'm guessing that the subject is particle physics, but I'm not familiar with this formula. Both the Baryon number and strangeness of a particle, for example, is related top the number of strange quarks and anti-strange quarks in a particle.
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Old Oct 4th 2016, 08:43 AM   #4
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Originally Posted by Jrt View Post
Hiya
Was wandering if anyone could explain the following:
n+ p - k+ x
Deduce the relative charge, baryon number and strangeness of particle x ?
Thanks
We have a rather large problem here. I'm presuming k stands for a kaon, which is a meson. The left hand side has two baryons, whereas the right hand side has at most one baryon (your mystery particle x.)

This reaction cannot happen if k is a kaon so there is no point in going further.

-Dan

Edit: Is your reaction actually $\displaystyle n \rightarrow p + K + x$? We can work with that one. (Dynamically this one can't happen either, but we can provide answers to your questions using this "reaction.")
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Last edited by topsquark; Oct 4th 2016 at 08:56 AM.
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