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 Oct 3rd 2016, 06:40 AM #1 Junior Member   Join Date: Oct 2016 Posts: 1 A level help Hiya Was wandering if anyone could explain the following: n+ p - k+ x Deduce the relative charge, baryon number and strangeness of particle x ? Thanks
 Oct 3rd 2016, 01:16 PM #2 Senior Member   Join Date: Aug 2010 Posts: 337 That makes no sense. Where did you find that expression? Was it part of an equation? What do "n", "p", "k", and "x" mean? You also ask about "particle x". Since the first expression involved adding and subtraction, I assumed that "n", "p", "k", and "x" were numbers. How did x become a particle? topsquark likes this.
 Oct 3rd 2016, 04:35 PM #3 Physics Team     Join Date: Jun 2010 Location: Morristown, NJ USA Posts: 2,289 I'm guessing that the subject is particle physics, but I'm not familiar with this formula. Both the Baryon number and strangeness of a particle, for example, is related top the number of strange quarks and anti-strange quarks in a particle.
Oct 4th 2016, 08:43 AM   #4

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 Originally Posted by Jrt Hiya Was wandering if anyone could explain the following: n+ p - k+ x Deduce the relative charge, baryon number and strangeness of particle x ? Thanks
We have a rather large problem here. I'm presuming k stands for a kaon, which is a meson. The left hand side has two baryons, whereas the right hand side has at most one baryon (your mystery particle x.)

This reaction cannot happen if k is a kaon so there is no point in going further.

-Dan

Edit: Is your reaction actually $\displaystyle n \rightarrow p + K + x$? We can work with that one. (Dynamically this one can't happen either, but we can provide answers to your questions using this "reaction.")
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Last edited by topsquark; Oct 4th 2016 at 08:56 AM.

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