Magnitude and direction of arm
Would like to know if this working is correct or not and help on part b?
I have for my answer of A) (after finding theta etc):
0 = ((12*9.81)*0.0365)+((1.5*9.81)*0.155)(Fy*0.05)
Fy = (42.9678+2.2808)/0.05
Fy = 904.972N
F being brachialis group muscles:
F=Fy/cos(theta)
F = 904.972/cos(13.39)
F = 930.26N
direction from positive x axis:
90+13.39 = 103.39degrees
No idea where to go from here for part b
