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Old Dec 1st 2016, 01:04 PM   #1
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Circuit help?

Hello I need help with a circuit problem.

If a 9v battery was connected to 4 1.1 ohm resistors in series, what would be the current through each bulb?
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Old Dec 1st 2016, 01:11 PM   #2
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Putting four 1.1 ohm resisters in series creates a total resistance of 4 x 1.1 = 4.4 ohms. If these are the only elements in the circuit then current flow = V/R = 9v/4.4 ohms. But you mentioned bulbs - what bulbs? Do you mean that the 1.1 ohm resistors are actually bulbs?
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Old Dec 1st 2016, 01:14 PM   #3
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There are 3 lightbulb through the the circuit, that is all problem gives me. What is said before, is exactly what it said.
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Old Dec 1st 2016, 01:26 PM   #4
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There must be a diagram to go with the question - if you can figure out how to post it that would be helpful. Does the circuit consist of 4 resistors and 3 bulbs all in series with the battery? If so, do you know anything about the resistance of each bulb?
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