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Old Feb 24th 2010, 11:06 AM   #1
Kev
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A Young's double slit problem

In a Young's double slit experiment, the distance between the slits and the screen is 1.60m and using light of wavelength 5.89x10^-7m the distance between the centre of the interference pattern and the fourth bright fringe on either side is 16.0mm. What is the slit separation?

I know about the equation w = λD/s
where w is the fringe separation,
D is the distance from slits to screen
and s is the slit spacing.

The problem I'm having is the w value. "the distance between the centre of the interference pattern and the fourth bright fringe on either side is 16.0mm." Any ideas?

Thanks in advance.
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Old Feb 24th 2010, 08:30 PM   #2
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You is good for you to write down what you know.

In this problem, you only need to find out the fringe separation. One thing you should notice is that the central bright fringe is the zero order one. The fringe separation is the same for each pair of successive bright fringe.

So the 4th bright fringe means it is 4 times the fringe separation and you can find the fringe separation by (16/4)mm
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Old Feb 25th 2010, 09:34 AM   #3
Kev
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Cheers! I'm glad I divided the number by 4 before handing in the work.
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