Physics Help Forum The convergent mirror in this problem is a part of...

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 Feb 21st 2010, 02:14 PM #1 Junior Member   Join Date: Feb 2010 Posts: 4 The convergent mirror in this problem is a part of... Please help me with this question? a) Hint: The convergent mirror in this problem is a part of a lens/mirror system so the object in this problem may be either real or virtual. Construct a ray diagram. Given: A real object is located to the left of a convergent mirror. The object's distance from the mirror and its focal length are shown in the figure below. http://i46.tinypic.com/2vb55ec.jpg The image is: 1. virtual, erect, and larger. 2. virtual, erect, and smaller. 3. real, inverted, and smaller. 4. real, inverted, and larger. 5. real, erect, and smaller. 6. virtual, inverted, and larger. 7. virtual, inverted, and smaller. 8. real, erect, and larger. b) The image distance is?: 1. -17/7f 2. 19/9f 3. -12/5 f 4. 14/9f 5. -19/9f 6. -3/2f 7.17/6f 8. 5/7f 9. 19/8f 10. 17/24f c)The magnification is?: 1. 4/15 2. -3/4 3. 3/8 4. -5/7 5. 13/4 6. -7/8 7.5/2 8. 5/19 9. 4/13 10. 11/3 Thank you so much in advance! I know it seems like a whole lot, but most of its answer choices =)
 Mar 1st 2010, 03:35 AM #2 Senior Member   Join Date: Dec 2008 Location: Udupi, Karnataka, India Posts: 292 Since the object is with the focus of the concave mirror, the image is virtual, erect and enlarged. to find the position of the image use 1/f = 1/do + 1/di. The magnification = di/do

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