woops forgot to post my attempt as well
so M = 0.30
we know that the distance of the object is 2 cm beyond the radius of curvature.
so we can express do as 2x + 2
the focal length will be x.
So what I did was:
M = di/do
0.30 = di/2x+2
(0.30)(2x+2) = di
Now I have an expression for di and do.
I plug it into the 1/f = 1/do + 1/di, but I don't know how to simplify it farther to get the answer.
