Go Back   Physics Help Forum > High School and Pre-University Physics Help > Light and Optics

Light and Optics Light and Optics Physics Help Forum

Reply
 
LinkBack Thread Tools Display Modes
Old Nov 16th 2009, 05:11 PM   #1
Junior Member
 
Join Date: Sep 2009
Posts: 15
Mirror's

An object is placed 2.0 cm beyond the centre of curvature of a concave mirror. If the magnification of this object is 0.30, what is the radius of curvature of this mirror?
quick.on.my.feet is offline   Reply With Quote
Old Nov 16th 2009, 08:57 PM   #2
Junior Member
 
Join Date: Sep 2009
Posts: 15
woops forgot to post my attempt as well

so M = 0.30

we know that the distance of the object is 2 cm beyond the radius of curvature.

so we can express do as 2x + 2

the focal length will be x.

So what I did was:

M = -di/do
0.30 = -di/2x+2
(0.30)(2x+2) = -di

Now I have an expression for di and do.

I plug it into the 1/f = 1/do + 1/di, but I don't know how to simplify it farther to get the answer.
quick.on.my.feet is offline   Reply With Quote
Old Nov 16th 2009, 09:38 PM   #3
Physics Team
 
Join Date: Feb 2009
Posts: 1,425
I think you have solved a similar one before.

Put - di = 0.6 f + 0.6 (remember x = f the focal length).

f = (do x di) / (d0 + di) and solve.
physicsquest is offline   Reply With Quote
Reply

  Physics Help Forum > High School and Pre-University Physics Help > Light and Optics

Tags
mirror



Search tags for this page
Click on a term to search for related topics.
Thread Tools
Display Modes


Similar Physics Forum Discussions
Thread Thread Starter Forum Replies Last Post
model with mirror suvadip Light and Optics 1 Sep 10th 2013 09:38 AM
Mirror Question jrodd321 Light and Optics 10 Jan 15th 2011 07:41 AM
Dielectric Mirror st3wart Advanced Optics 0 Jul 13th 2010 08:08 PM
concave mirror Scott Light and Optics 2 Mar 31st 2009 09:12 PM
plane mirror iamanoobatphysics Light and Optics 1 Dec 2nd 2008 09:38 PM


Facebook Twitter Google+ RSS Feed