Physics Help Forum Mirror's

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 Nov 16th 2009, 05:11 PM #1 Junior Member   Join Date: Sep 2009 Posts: 15 Mirror's An object is placed 2.0 cm beyond the centre of curvature of a concave mirror. If the magnification of this object is 0.30, what is the radius of curvature of this mirror?
 Nov 16th 2009, 08:57 PM #2 Junior Member   Join Date: Sep 2009 Posts: 15 woops forgot to post my attempt as well so M = 0.30 we know that the distance of the object is 2 cm beyond the radius of curvature. so we can express do as 2x + 2 the focal length will be x. So what I did was: M = -di/do 0.30 = -di/2x+2 (0.30)(2x+2) = -di Now I have an expression for di and do. I plug it into the 1/f = 1/do + 1/di, but I don't know how to simplify it farther to get the answer.
 Nov 16th 2009, 09:38 PM #3 Physics Team   Join Date: Feb 2009 Posts: 1,425 I think you have solved a similar one before. Put - di = 0.6 f + 0.6 (remember x = f the focal length). f = (do x di) / (d0 + di) and solve.

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