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 Jul 2nd 2009, 07:24 PM #1 Junior Member     Join Date: Jun 2009 Posts: 11 optics first of all from the question i was unable to understand what is meant by the term they both have same no of waves and how do we apply the concept over here (note the red one cube is made of material A and green one of material B and blue of material c) Attached Thumbnails   __________________ bindaas boy....... Last edited by abhishek arora; Jul 2nd 2009 at 07:27 PM.
 Jul 3rd 2009, 09:25 AM #2 Senior Member   Join Date: Dec 2008 Location: Udupi, Karnataka, India Posts: 292 The refractive index μ = c/v = fλο/fλ = λο/λ Νumber of waves in a slab of thickness t = n = t/λ or n/t = 1/λ So μ= λο/λ= λοn/t. For A 3/2 = λο*n/t.........(1) For B μB = λο*n1/(t/3) ......(2) For C 1.6 = λο*n2/(2t/3)...(3) Form eq. 1, 2 and 3 find n, n1 and n2. Now n = n1 + n2. Substitutes the values of n, n1 and n2 and find μB.

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