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Old Jul 2nd 2009, 07:24 PM   #1
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optics

first of all from the question i was unable to understand what is meant by the term they both have same no of waves and how do we apply the concept over here
(note the red one cube is made of material A and green one of material B and blue of material c)
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Last edited by abhishek arora; Jul 2nd 2009 at 07:27 PM.
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Old Jul 3rd 2009, 09:25 AM   #2
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The refractive index μ = c/v = fλο/fλ = λο/λ
Νumber of waves in a slab of thickness t = n = t/λ or n/t = 1/λ
So μ= λο/λ= λοn/t.
For A 3/2 = λο*n/t.........(1)
For B μB = λο*n1/(t/3) ......(2)
For C 1.6 = λο*n2/(2t/3)...(3)
Form eq. 1, 2 and 3 find n, n1 and n2.
Now n = n1 + n2. Substitutes the values of n, n1 and n2 and find μB.
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