Physics Help Forum I have my exam soon so help asap would be appreciated!

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 Jun 11th 2009, 08:21 PM #1 Junior Member   Join Date: Jun 2009 Posts: 5 I have my exam soon so help asap would be appreciated! Hi, I am having trouble with this question. I'm not really sure what formula to use and how i would find the degrees. Any help would be appreciated! For a slit width 3.0 x 10^-6 m, illuminated by light of wavelength 550nm, find the width of the central maximum, in degrees.
 Jun 12th 2009, 09:26 PM #2 Senior Member   Join Date: Apr 2008 Location: HK Posts: 886 You should use $\displaystyle a sin\theta = m\lambda$ a is the separation of the slit width, $\displaystyle \theta$ refers to the angle of the m th minima measured from the centre of the slit, m is the order of minima, $\displaystyle \lambda$ is the wavelength So you put 1 into the equation and you find $\displaystyle \theta$ since it only includes half of the central maximum, so central maximum should have $\displaystyle 2\theta$
 Jun 14th 2009, 05:37 PM #3 Junior Member   Join Date: Jun 2009 Posts: 5 Thank you so much for the help!

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