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 Mar 31st 2009, 06:25 PM #1 Junior Member   Join Date: Mar 2009 Posts: 2 concave mirror I keep getting the wrong answer to this problem. I'm sure I'm making a stupid mistake somewhere, but can't figure out what's wrong. I'd really appreciate any help. QUESTION: It is observed that the size of a real image formed by a concave mirror is four times the size of the object when the object is 30.0 cm in front of the mirror. What is the radius of curvature of this mirror? ATTEMPT: M = -Xi/Xo = -4 Xi = 4Xo 1/Xo + 1/(4Xo) = 1/f f = 4/5 Xo 3Xo = 0.3m f= 4/5 (0.1) = 0.08 R = 2f = 2(0.08) = 0.16 I know I'm doing something wrong here...
 Mar 31st 2009, 07:11 PM #2 Physics Team   Join Date: Feb 2009 Location: India Posts: 365 Object distance u = Xo = -30 Image distance v =4Xo = -120 -1/30 - 1/120 = 1/f f = -24 cm
 Mar 31st 2009, 09:12 PM #3 Junior Member   Join Date: Mar 2009 Posts: 2 thank you Thanks a lot Parvez! I see where I was messing up. Now to calculate the radius of curvature, I just take 2F (2 x 24 in this case) Thanks again!!

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### the height of the real image formed by a concave mirror is four times the object height when the object is 30.0

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