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Old Dec 14th 2008, 08:51 AM   #1
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Glass Slab question

The velocity of light in a medium is 2 * 10^8 m/s. A ray of light is incident at the interface of the medium on the optically denser side at 30◦ . What is the angle for refraction ?


Now, I'm confused..is it possible to find this answer? THe abosolute refractive index is not given, we could apply snell's law but we get 2 variables, and we I can't seem to get simultaneous equations.. please help.


EDIT: THIS IS NOT A GLASS SLAB QUESTION, SORRY FOR MY TITLE!!!

Last edited by ice_syncer; Dec 14th 2008 at 09:22 AM. Reason: Becasue THIS IS NOT A GLASS SLAB QUESTION, SORRY FOR MY TITLE!!!
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Old Dec 14th 2008, 09:21 AM   #2
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Originally Posted by flyingsquirrel View Post
Hi,

Can't you use this :

to get the refractive index ?
That will only give the absolute refractive index(with respect to air , yeah we can use 3*10^8 for that..), not with respect to the other medium.. Please shjow the steps also.
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Old Dec 15th 2008, 01:57 PM   #3
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The index of refraction is the ration between the speed in air (vacuum) and the speed in the medium.
Here n=3x10^8/2x10^8=1.5 (ordinary glass)
I will assume that the light goes from glass to air if the problem does not specify the second medium.
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