User Name Remember Me? Password

 LateX Help LateX Help - Test your LaTex skills and get help with using LaTex Mar 31st 2017, 03:13 PM #1 Senior Member   Join Date: Apr 2015 Location: Somerset, England Posts: 1,035 Test $\displaystyle \left( {\begin{array}{*{20}{c}} {{a_{11}}} & {{a_{12}}} \\ {{a_{21}}} & {{a_{22}}} \\ \end{array}} \right)$ $\displaystyle \sum\nolimits_{n = 1}^\infty {{n^2}}$ $\displaystyle \sum\nolimits_{n = 1}^\infty {{n^2}}$ $\displaystyle \sqrt {{a^2} + {b^2}}$ $\displaystyle \sqrt {{a^2} + {b^2}}$ So mathml now works here, that's really useful. not sure what's wrong with the tex version though. Last edited by studiot; Mar 31st 2017 at 03:19 PM.   Mar 31st 2017, 04:23 PM   #2

Join Date: Apr 2008
Location: On the dance floor, baby!
Posts: 2,818
 Originally Posted by studiot $\displaystyle \left( {\begin{array}{*{20}{c}} {{a_{11}}} & {{a_{12}}} \\ {{a_{21}}} & {{a_{22}}} \\ \end{array}} \right)$ $\displaystyle \sum\nolimits_{n = 1}^\infty {{n^2}}$ $\displaystyle \sum\nolimits_{n = 1}^\infty {{n^2}}$ $\displaystyle \sqrt {{a^2} + {b^2}}$ $\displaystyle \sqrt {{a^2} + {b^2}}$ So mathml now works here, that's really useful. not sure what's wrong with the tex version though.
There isn't anything wrong with the coding, it's just that the tex tags don't work any more.

-Dan
__________________
Do not meddle in the affairs of dragons for you are crunchy and taste good with ketchup.

See the forum rules here.   Apr 1st 2017, 12:55 AM #3 Senior Member   Join Date: Apr 2015 Location: Somerset, England Posts: 1,035 Thanks.   Jun 24th 2017, 02:27 PM   #4
Senior Member

Join Date: Nov 2013
Location: New Zealand
Posts: 552
 Originally Posted by studiot $\displaystyle \left( {\begin{array}{*{20}{c}} {{a_{11}}} & {{a_{12}}} \\ {{a_{21}}} & {{a_{22}}} \\ \end{array}} \right)$ $\displaystyle \sum\nolimits_{n = 1}^\infty {{n^2}}$ $\displaystyle \sum\nolimits_{n = 1}^\infty {{n^2}}$ $\displaystyle \sqrt {{a^2} + {b^2}}$ $\displaystyle \sqrt {{a^2} + {b^2}}$ So mathml now works here, that's really useful. not sure what's wrong with the tex version though.
testing....

$\displaystyle \frac{1}{\sqrt{1-\frac{v^2}{c^2}}}$  Tags test Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Physics Forum Discussions Thread Thread Starter Forum Replies Last Post kiwiheretic LateX Help 3 Jul 14th 2016 05:52 AM MathGuru LateX Help 35 Feb 21st 2010 05:55 PM angelica Kinematics and Dynamics 1 Feb 10th 2009 02:15 AM angelica Kinematics and Dynamics 0 Feb 8th 2009 03:02 PM