Physics Help Forum inclined slope, b degrees

 Kinematics and Dynamics Kinematics and Dynamics Physics Help Forum

 Nov 26th 2008, 02:08 PM #1 Junior Member   Join Date: Nov 2008 Posts: 21 inclined slope, b degrees as in the diagram below, mass m1 is placed above mass m2 on a sloped incline with an angle of b degrees. the frictional coefficient between the two masses is C1 and the coeficient between mass 2 and the slope is C2. find the acceleration of the masses. Picasa Web Albums - Devan - Drop Box after dividing the vectors into components i said N1=(m1)gcosb f1=(C1)(m1)gcosb N2=N1+(M2)gcosb=(M1+M2)gcosb f2=(C2)(M1+M2)gcosb for mass 1 F=m1gsinb-f1=m1a =(m1)gsinb-(C1)(m1)gcosb=m1a a1=g(sinb-C1cosb)=gcosb(tgb-C1) meanin that when C1 is equal to tanb, body 1 will not move relative to body 2 or will not move relative to the slope? now for body2 F=m2gsinb+f1-f2=m2a------> is this correct?? after opening i get a2=m2gcosb(tgb-C2)+m1gcosb(C1-C2) is this correct?
Nov 27th 2008, 07:24 PM   #2
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 Originally Posted by devanlevin a1=g(sinb-C1cosb)=gcosb(tgb-C1) meanin that when C1 is equal to tanb, body 1 will not move relative to body 2 or will not move relative to the slope? a2=m2gcosb(tgb-C2)+m1gcosb(C1-C2) is this correct?
Yes. you are correct

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