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Old Nov 9th 2013, 09:50 PM   #1
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Really confused... Piano problem

A 350 kg piano needs to be moved up the incline plane of 3.7 meters. If the angle of incline is 68 degrees, and the man pushes with a force parallel to the incline plane, and makes the piano move with an accelartion of 0.5 m/s^2. If the coefficient of friction is 0.31, what is the force exerted by the man?

Honesty don't know how to try or start this problem. I have a faint idea, but still... I would appreciate some kind of help.

Thank you in advance and do you fellows have any tips on how to tackle problems that deal with incline planes?
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Old Nov 10th 2013, 02:07 AM   #2
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Piano on inclined plane.

Since the piano is being pushed up the incline, Friction will be acting down the slope. If F is the force with which it is being pushed, this minus (the component of weight down the plane + friction) will give the net force. Divide this by m to get acceleration.
Hope this helps
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Old Nov 10th 2013, 09:47 AM   #3
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Thanks!

Problem is they gave me the accelration already which is 0.5. You said in order to get the total net force it's Fman=F-(weight of piano+force of friction)

I guess the weight is mg=(350)(9.8)=3430N

Force of friction is Ff=(0.41)(3430)cos(68)=526N?

I don't know if I'm on the right track.
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Old Nov 10th 2013, 11:07 AM   #4
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Yes you are. Just plug in the value for acceleration and find F
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