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Old Sep 6th 2013, 05:41 AM   #1
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geostationary satellite

there's a geostationary satellite that is orbiting the earth at a height of about 6R above the earth's surface where R is the radius of the earth. If there is another geostationary satellite orbiting earth at the height of 2.5R from the surface of earth, what will be time period of latter geostationary satellite?
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Old Sep 6th 2013, 06:59 AM   #2
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In order for a satellite to be in geostationary orbit it must be at a distance from the earth that corresponds to one orbit per day. That distance is indeed about 6R. The satellite at 2.5R will not be in a geostationary orbit but instead will orbit a faster rate than the required rate to be geostationary.

The fundamental equation of orbital mechanics is

GM = w^2 r^3

where M is the mass of the earth, w is rotational velocity of the satellite, and r is the distance of the satellite above the center of the earth. Thus for any two satellites in earth orbit GM is a constant and you have:

w_1^2 r_1^3 = w_2^2 r_2^3

From this you can ascertain what happens to w with changing values of r.

Last edited by ChipB; Sep 6th 2013 at 07:12 AM.
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Old Sep 6th 2013, 11:49 AM   #3
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F = mA Solution

Hi adaliciamala...

Here is a solution using d(mV/dt) = sumF. (i.e., f = mA )

Two circular vector representations are developed.

http://www.thermospokenhere.com/wp/0...tationary.html


http://www.thermospokenhere.com/wp/0..._circular.html

Good Luck with your studies.

Thermo...
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