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 Sep 10th 2012, 03:20 PM #1 Junior Member   Join Date: Sep 2012 Posts: 1 Statics This problem has stumped me greatly. If the magnitude of the resultant force is to be 500N, directed along the positive y-axis, determine the magnitude of force F and its direction (theta). The picture is on an x-y plane; there's a force 15 degrees below the negative x-axis and has a magnitude of 700N. That's all the information the problem has given me. Can someone please explain how I go about doing this?
 Sep 11th 2012, 06:04 AM #2 Physics Team     Join Date: Jun 2010 Location: Morristown, NJ USA Posts: 2,354 I'n guessing from your description that you have a force which I'll call F1 with magnitude 700N plus an unknown force F, and that these two forces added together result in a combined force R of 500N in the positive-y direction. In other words: F1 + F = R To find F simply subtract F1 from both sides: F = R-F1 Please note that F, F1 and R are all vectors, so this requres vector subtraction. Can you finish it from here?

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if the magnitude of the resultant force is to be 500 N directed along the positive y axis determine the magnitude of force F and its direction theta

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