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 Sep 17th 2011, 04:05 PM #1 Junior Member   Join Date: Sep 2011 Posts: 1 Average Accleration Please solve this questions or list down the formulas Find the magnitude of average acceleration of the tip of the second hand of length 10cm during 10sec
 Sep 18th 2011, 05:32 AM #2 Physics Team     Join Date: Jun 2010 Location: Mauritius Posts: 609 This seems more like an experiment that you need to perform to get results... Be well aware that the practice answer might not be what theory suggests because of several factors in play during practice and that my answer (which will be theory) might very well be off the answer your teacher is looking for. In 1 sec, the second hand moves 6 degrees from rest, to rest, reaching maximum speed in the middle of its course. Initial point is at 0, and final point is at (2pi(10)*6/360) cm. Use v = u + at. v is final velocity u is initial velocity a is acceleration you're looking for t is the time taken. __________________ Jerry (Got my results!) It is easier to protect your feet with slippers than to cover the earth with carpet. No one can go back and change a bad beginning; but anyone can start now and create a successful ending. If a problem can be solved, no need to worry about it. If it cannot be solved what is the use of worrying?
 Sep 21st 2011, 03:46 PM #3 Physics Team     Join Date: Jun 2010 Location: Naperville, IL USA Posts: 2,271 If yuo can assume that the second hand moves at a constant speed (i.e, not stopping and starting each second the way Jerry described), then the rotational velocity is w=2 pi radians/minute = 2 pi/60 radians/second. The centripedal acceleration of the tip of the second hand can then be found from a = w^2r.

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