Well, I would do it like that.
1. Assume that m is larger and instead is pulling M up, and the force of friction is just opposing the downfall of m.
2. Assume that m is smaller and M pulls m up the ramp, with friction just preventing m to move up.
First case:
On M, we have:
T - Mg = 0
On m,
mg sinA = µ mg cosA + T
You can work on the highest value of m. (Let that be x)
Case 2:
T - Mg = 0
mg sinA + µ mg cosA = T
You get the lower boundary. (Let that be y)
Then, the interval is: y <= m <= x
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Jerry (Got my results!) It is easier to protect your feet with slippers than to cover the earth with carpet.
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