Physics Help Forum Verticle projectile - check my work?

 Kinematics and Dynamics Kinematics and Dynamics Physics Help Forum

 Mar 24th 2011, 02:22 AM #1 Junior Member   Join Date: Mar 2011 Posts: 7 Verticle projectile - check my work? Hi, have I got this correct? An object is projected directly upwards and 0.2 seconds after launch it has reached a height of 0.57 meters. A) What is the initial speed as it lifts off the ground? B) What is its speed at a height of .57 meters? c) How much higher does it go? A) X-X0 = V0t + 0.5At^2 0.57-0 = V0(0.2) -4.9(0.2)^2 0.57 + 0.196 = V0(0.2) V0 = 0.766/0.2 V0 = 3.83M/S B) V = V0 + At V = 3.83 + (-9.8)(0.2) V = 1.87M/S C) V^2 = V0^2 + 2A(X-X0) 0 = 3.83^2 + 2(-9.8)(X-0) -14.6689 = -19.6(X) X = -14.6689/-19.6 X = 0.7484m (Maximum height) 0.7484 - 0.57 = The object travels 0.1784m higher than the height achieved at the 0.2 second mark. Thanks Splint
 Mar 24th 2011, 05:25 AM #2 Member   Join Date: Oct 2008 Posts: 66 Don't see any errors straight up.
 Mar 24th 2011, 11:09 AM #3 Forum Admin     Join Date: Apr 2008 Location: On the dance floor, baby! Posts: 2,494 @ Splint This might seem to be a little picky, but it's important none the less. Physics is "case sensitive." That is to say, for example, the symbol for acceleration is not "A" it is "a." Different meanings are attached to the two symbols. (A usually stands for an amplitude of a wave, and a is an acceleration.) The same comment applies to units. The unit for velocity is not "M/S" it is "m/s." -Dan __________________ Do not meddle in the affairs of dragons for you are crunchy and taste good with ketchup. See the forum rules here.

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