The speed of the water along the horizontal would be given by:

Speed = Distance / Time

As the horizontal speed is 10 m and the time 2 seconds, what is the horizontal distance, which is the street's width?

Along the vertical, you have another equation. The one I tld you earlier.

s = ut + 0.5 at^2

The initial speed here is 20 m/s, your time 2 s and the acceleration due to gravity is a.

Depending on the directions that you take, you will have to take the acceleration as negative or positive, but my advice is to take the upwards direction as positive.

Hence, your vertical initial speed is + 20m/s, the acceleration due to gravity is then - 9.8 m/s^2 (or you can use 10 m/s^2 depending on what value you are asked to use).

Post what you get!