Physics Help Forum Time, Range, and Height

 Kinematics and Dynamics Kinematics and Dynamics Physics Help Forum

 Sep 14th 2008, 11:46 AM #1 Junior Member   Join Date: Sep 2008 Posts: 9 Time, Range, and Height A stationary ball is kicked so that it moves away at 24 m/s and at an angle of 19 degrees above the ground. Determine the ball's A) hang-time, B) maximum range, & C) maximum height. Can someone please help me with this? PB
 Sep 14th 2008, 02:16 PM #2 Senior Member     Join Date: Apr 2008 Posts: 815 I will help you but not do all for you. $\displaystyle a_y(t)=-9.8 m/s^2$. $\displaystyle v_y(t)=-9.8t+v_{0y}=-9.8t+24\sin 19°$ so $\displaystyle y(t)=-4.9t^2+24\sin 19°t$. While for the x-axis, $\displaystyle a_x(t)=0$. $\displaystyle v_x(t)=v_{0x}=24\cos 19°$ so $\displaystyle x(t)=24\cos 19°t$. Maximum height is when $\displaystyle v_{0y}=0$, just solve it. Hang-time is when you solve for t when $\displaystyle y(t)=0$. And maximum range is when $\displaystyle y(t)=0$, solve for $\displaystyle t$ and substitute this $\displaystyle t$ into $\displaystyle x(t)$. And don't forget the units. __________________ Isaac If the problem is too hard just let the Universe solve it.

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