Originally Posted by **decoy808** just would like to check a few question if im doing them right. thanks
(a)
Find by calculation, the horizontal and vertical components of a force 50N which is acting at 40degrees to the horizontal.
50sin40 = 32.1
50cos40 = 38.3
(b)the horizontal and vertical components of a force are respectively 20N and 30N calculate the magnitude and direction of the force.
tan-1 = 20/ 30 = 33.7degreess? |

50sin(40) = vertical

50cos(40)= horizontal

Other way around on (b) tan^-1(30/20)=56.3 degrees

Note: when using tan^-1 always divide the vertical by the horizontal.

magnitude will be sq-rt (20^2+30^2) = 36.05 N