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Old Nov 23rd 2009, 02:05 PM   #1
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Vectors

just would like to check a few question if im doing them right. thanks

(a)
Find by calculation, the horizontal and vertical components of a force 50N which is acting at 40degrees to the horizontal.

50sin40 = 32.1
50cos40 = 38.3

(b)the horizontal and vertical components of a force are respectively 20N and 30N calculate the magnitude and direction of the force.

tan-1 = 20/ 30 = 33.7degreess?
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Old Nov 23rd 2009, 02:44 PM   #2
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Originally Posted by decoy808 View Post
just would like to check a few question if im doing them right. thanks

(a)
Find by calculation, the horizontal and vertical components of a force 50N which is acting at 40degrees to the horizontal.

50sin40 = 32.1
50cos40 = 38.3

(b)the horizontal and vertical components of a force are respectively 20N and 30N calculate the magnitude and direction of the force.

tan-1 = 20/ 30 = 33.7degreess?
50sin(40) = vertical
50cos(40)= horizontal

Other way around on (b) tan^-1(30/20)=56.3 degrees

Note: when using tan^-1 always divide the vertical by the horizontal.

magnitude will be sq-rt (20^2+30^2) = 36.05 N

Last edited by Paul46; Nov 23rd 2009 at 02:55 PM.
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Old Nov 24th 2009, 06:17 PM   #3
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Originally Posted by decoy808 View Post
just would like to check a few question if im doing them right. thanks

(a)
Find by calculation, the horizontal and vertical components of a force 50N which is acting at 40degrees to the horizontal.

50sin40 = 32.1
50cos40 = 38.3

(b)the horizontal and vertical components of a force are respectively 20N and 30N calculate the magnitude and direction of the force.
Please explain how you went from the correct results you arrived at in part a to what you obtained in part b, which is incorrect.
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