Go Back   Physics Help Forum > High School and Pre-University Physics Help > Kinematics and Dynamics

Kinematics and Dynamics Kinematics and Dynamics Physics Help Forum

Reply
 
LinkBack Thread Tools Display Modes
Old Oct 28th 2009, 12:32 PM   #1
Senior Member
 
Join Date: Sep 2009
Location: St. John's, NL
Posts: 124
distance !



A 3.62 kg block located on a horizontal floor is pulled by a cord that exerts a force F = 12.4 N at an angle theta = 20.0 above the horizontal, as shown in the Figure. The coefficient of kinetic friction between the block and the floor is 0.07. What distance does the block travel in a time of 3.70 s after it starts moving?


hmm
Fn= 3.62 * 9.8 = 35.5 N

how do i do this problem?
christina is offline   Reply With Quote
Old Oct 28th 2009, 01:19 PM   #2
Senior Member
 
Join Date: Sep 2009
Location: india
Posts: 409
17.89 metres?
vertical force balance gives mg=N+ F sin theta, so N= mg- F sin theta
SO Fric= mew k N= mew k (mg -F sin theta)
so net horizontal force= Fcos theta - mew k (mg- F sin theta)
net horizontal acc= above found force/ mass
use s= 1/2 acc *t^2 (t given=3.7)
r.samanta is offline   Reply With Quote
Old Oct 28th 2009, 06:26 PM   #3
Senior Member
 
Join Date: Sep 2009
Location: St. John's, NL
Posts: 124
aha... thank you !!!
christina is offline   Reply With Quote
Reply

  Physics Help Forum > High School and Pre-University Physics Help > Kinematics and Dynamics

Tags
distance



Thread Tools
Display Modes


Similar Physics Forum Discussions
Thread Thread Starter Forum Replies Last Post
Distance ? Saloom Energy and Work 2 Apr 5th 2013 03:18 PM
distance of a body stealth Kinematics and Dynamics 5 Mar 13th 2010 10:47 AM
vectors for distance juggalomike Advanced Mechanics 1 Jan 14th 2010 05:49 AM
spring distance Book Periodic and Circular Motion 1 Dec 7th 2009 10:22 PM
distance...? christina Kinematics and Dynamics 2 Nov 30th 2009 12:20 AM


Facebook Twitter Google+ RSS Feed