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Old Oct 25th 2009, 05:27 PM   #1
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Time it takes a monkey to climb a rope with out breaking it...

A 13.5 kg monkey starts to climb a long rope to reach a banana located at a height of 6.92 m. The rope will snap if the tension exceeds 148.50 N. Calculate the least amount of time the monkey could take to reach the banana without breaking the rope.

I don't even know where to start...
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Old Oct 25th 2009, 06:17 PM   #2
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Originally Posted by Milarkey View Post
A 13.5 kg monkey starts to climb a long rope to reach a banana located at a height of 6.92 m. The rope will snap if the tension exceeds 148.50 N. Calculate the least amount of time the monkey could take to reach the banana without breaking the rope.

I don't even know where to start...
If the tension of the rope is 148.50 N (the rope won't break), what is the acceleration of the monkey?
Hint :
Spoiler:
Use Newton's second law
.
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Old Oct 25th 2009, 09:37 PM   #3
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T-mg=ma, least time, so allow max tension for max acc. so a=(T-mg)/m=1.2m/s^2. use 6.92=1/2 a t^2 to get t=3.4 seconds.
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