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Old Sep 28th 2009, 10:58 PM   #1
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Velocity and Displacement

A particle's initial velocity is given by v0x = -1.0m/s and v0y = 3.0m/s; it's acceleration is ax = 0.50m/s2 and ay = -0.90m/s2. (a) Calculate its velocity 2.0s later. (b) Calculate its displacement at that time.

vx = v0x + axt
∆x = v0xt + 1/2axt2
∆y = v0yt + 1/2ayt2

v = -1.0m/s(x hat) + 3.0m/s(y hat)
a = 0.5m/s2(x hat) - 0.9m/s2(y hat)

Solve for velocity at 2.0s
vx = v0x + axt
vx = (-1m/s) + (0.5m/s2)(2.0s)
vx = 0m/s

vy = v0y + ayt
vx = (3m/s) + (-0.9m/s2)(2.0s)
vx = 1.2m/s

v = 0m/s(x hat) + 1.2m/s(y hat)

Calculate displacement.
∆x = v0xt + 1/2axt2
∆x = (-1m/s)(2.0s) + 1/2(0.5m/s2)(2.0s)2
∆x = -1m

∆y = v0xt + 1/2axt2
∆y = (3m/s)(2.0s) + 1/2(-0.9m/s2)(2.0s)2
∆y = 4.2m

y = -1.0m(x hat) + 4.2m(y hat)
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Old Sep 29th 2009, 02:04 AM   #2
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Looks OK to me.
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