Solidsnake,
You have already asked a similar question to this on the 5/9/09 called **Mastering Physics practice question. ** I know this because i made a complete mess of it myself until physicsquest came along, i understand the equation now. (Thanks to physicsquest)
u=initial velocity
v=final velocity
t=time
a=acceleration
s=displacement
to find the altitude (s) you first need to find the velocity (v), v= u + at
u=0 , a=33m/s^2 , t=32, v=0+ 33 x 32 = 1056 m/s
displacement (s) after fuel runs out = v^2 = 0= u^2 - 2as (a= being gravity, 9.8)
1056^2 = 1115136 (take into account that v becomes u)
1115136-1115136 = v^2, (v^2 in this case will be 0)
1115136/(2a) = s
s= 56894.69 m, after fuel runs out
t = s/((u+v)/2)
t= 56894.69/((1056+0)/2) = 107.755 secs, after fuel runs out
I'll leave you to find the rest, you still need to find (t) & (s) when the rocket had fuel and like Deco stated mass is irrelevant if your given (a) & (t), so you only need to find (s).
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Last edited by Paul46; Sep 27th 2009 at 07:56 AM.
Reason: spelling
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