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Old Apr 12th 2009, 02:08 AM   #1
s3a
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Determine the net force. State in which case the object could be at rest.

The pencil markings for Practice Question #1 is what I got but the answers are:

1. 1N[E]
2. 2N[N]
3. 0N

For #1 and #2, why do I get the exact opposite in direction?

Thanks!
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Determine the net force. State in which case the object could be at rest.-q.jpeg  
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Old Apr 12th 2009, 05:09 AM   #2
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1. When the two forces act in opposite direction, the resultant or net force is equal to the difference of the two and towards larger force.The 4n force is due east and the 3N force is due west. Hence the net force = 4N-3N = 1N is due east. ( in diagrams east always points towards right and north upward as shown in the adjecent fig in your book.

2.5N force due east is balanced by (3N+2N) force duye west. The unbalanced force of 2N is due north
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Old Apr 12th 2009, 01:48 PM   #3
s3a
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Ohhhhhh! It's because, it asks to determine the NET FORCE!!! I was thinking that it's asking me to find out the force that it will need in order to BE AT REST.

Am I understanding this right now?
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Old Apr 12th 2009, 07:59 PM   #4
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Yes. Now you are right now.
Unbalanced force means the force which has no force opposite to it to balance.
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