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Old Apr 6th 2009, 06:40 AM   #1
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Is this a constant or variable force?

F(net) = (umg + 1/2*rho*A*v^2)

If it is constant I can describe the work done as

W = F(net)delta(r)

If it varies I need to describe it as

W(net) = integral from s0 to sf of (F(net).dr)
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Old Apr 9th 2009, 05:59 AM   #2
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What is A?

As F is function of $\displaystyle v^2$, and supposing that is not equal to zero, there will be an acceleration so v will change and so F.
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Old Apr 9th 2009, 09:03 AM   #3
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You haven't specified what all the other terms are and the conditions under which this occurs. This looks like a combination of friction and drag.
In general it looks like a variable force as v^2 is present. The net force can cause deceration and a slowing down which will affect F. However if there is some mechanism by which v is maintained constant, then F too will be a constant.
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