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Old Jul 1st 2018, 01:18 AM   #1
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A question on physics kinematics

The velocity of a particle moving in the positive direction I of the x axis varies as v=a*root of x,where a is a +'ve constant .assuming that at moment t=0 the particle was located at the point x=0.find:
A)the time dependence of the velocity and acceleration of the particle
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Old Jul 1st 2018, 02:58 AM   #2
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Originally Posted by Mithilaa View Post
The velocity of a particle moving in the positive direction I of the x axis varies as v=a*root of x,where a is a +'ve constant .assuming that at moment t=0 the particle was located at the point x=0.find:
A)the time dependence of the velocity and acceleration of the particle
We don't do people's homework for them. Please read the forum rules.
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Old Jul 1st 2018, 04:12 AM   #3
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Assuming that by "root of x" you mean the square root, $\displaystyle x^{1/2}$, "v= a root of x" is $\displaystyle \frac{dx}{dt}= ax^{1/2}$. That can be written as $\displaystyle x^{-1/2}dx= a dt$. Integrate.
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Old Jul 1st 2018, 05:21 AM   #4
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My doubt is how to integrate
Is it 2* root of x equals to at
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Old Jul 1st 2018, 05:22 AM   #5
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I guess hoi thinks the rules don't apply to him.
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Old Jul 1st 2018, 05:25 AM   #6
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I actually have the solution of this question but I have some doubts on the question.thats why I asked it

Last edited by Mithilaa; Jul 1st 2018 at 05:29 AM.
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Old Jul 1st 2018, 05:26 AM   #7
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I am sorry .it was my mistake
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Old Jul 1st 2018, 05:23 PM   #8
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Originally Posted by Mithilaa View Post
I actually have the solution of this question but I have some doubts on the question.thats why I asked it
In a situation like that, show us, not only what solution you have, but how you got that solution.
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