Physics Help Forum A question on physics kinematics

 Kinematics and Dynamics Kinematics and Dynamics Physics Help Forum

 Jul 1st 2018, 02:18 AM #1 Junior Member   Join Date: Jul 2018 Posts: 4 A question on physics kinematics The velocity of a particle moving in the positive direction I of the x axis varies as v=a*root of x,where a is a +'ve constant .assuming that at moment t=0 the particle was located at the point x=0.find: A)the time dependence of the velocity and acceleration of the particle
Jul 1st 2018, 03:58 AM   #2
Physics Team

Join Date: Apr 2009
Location: Boston's North Shore
Posts: 1,573
 Originally Posted by Mithilaa The velocity of a particle moving in the positive direction I of the x axis varies as v=a*root of x,where a is a +'ve constant .assuming that at moment t=0 the particle was located at the point x=0.find: A)the time dependence of the velocity and acceleration of the particle
We don't do people's homework for them. Please read the forum rules.

 Jul 1st 2018, 05:12 AM #3 Senior Member   Join Date: Aug 2010 Posts: 383 Assuming that by "root of x" you mean the square root, $\displaystyle x^{1/2}$, "v= a root of x" is $\displaystyle \frac{dx}{dt}= ax^{1/2}$. That can be written as $\displaystyle x^{-1/2}dx= a dt$. Integrate. topsquark likes this.
 Jul 1st 2018, 06:21 AM #4 Junior Member   Join Date: Jul 2018 Posts: 4 My doubt is how to integrate Is it 2* root of x equals to at
 Jul 1st 2018, 06:22 AM #5 Physics Team   Join Date: Apr 2009 Location: Boston's North Shore Posts: 1,573 I guess hoi thinks the rules don't apply to him.
 Jul 1st 2018, 06:25 AM #6 Junior Member   Join Date: Jul 2018 Posts: 4 I actually have the solution of this question but I have some doubts on the question.thats why I asked it Last edited by Mithilaa; Jul 1st 2018 at 06:29 AM.
 Jul 1st 2018, 06:26 AM #7 Junior Member   Join Date: Jul 2018 Posts: 4 I am sorry .it was my mistake
Jul 1st 2018, 06:23 PM   #8
Senior Member

Join Date: Aug 2010
Posts: 383
 Originally Posted by Mithilaa I actually have the solution of this question but I have some doubts on the question.thats why I asked it
In a situation like that, show us, not only what solution you have, but how you got that solution.

 Tags kinematics, physics, question

 Thread Tools Display Modes Linear Mode

 Similar Physics Forum Discussions Thread Thread Starter Forum Replies Last Post Qwertyzxc Kinematics and Dynamics 2 Jan 10th 2013 07:55 AM xtheunknown0 Kinematics and Dynamics 1 Dec 25th 2010 06:42 PM s3a Kinematics and Dynamics 0 Feb 2nd 2010 07:15 PM oblixps Kinematics and Dynamics 6 Sep 10th 2009 11:38 PM walton01 Kinematics and Dynamics 1 Jan 25th 2009 09:21 PM