**2.38 throw a glob of puddy straight up**
you throw a glob of puddy straight up toward the ceiling.
which is **3.00** m above the point where the puddy leaves your hand.
the initial *speed* of the putty as it leaves your hand is **9.70 m/s**
a. What is the *speed* of the puddy just before it strikes the ceilng?
\begin{align*}\displaystyle
V_f^2 &= V_0^2 + 2ad \\
&=(9.7)^2 + 2(-9.8)(3)\\
&= 94.9-58.8\\
&= 36.1\\
V_f&\approx\color{red}{6 m/s}
\end{align*}
b, How much time from when it leaves your and does it take the puddy to reach the ceiling?
\begin{align*}\displaystyle
(6-9.7)/t&=-9.8\\
-3.7t&=-9.8\\
t&=\frac{-9.8}{-3.7}\\
t&\approx\color{red}{2.65s}
\end{align*}
just seeing if this is correct
and suggestions
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Last edited by countdown; Jan 17th 2018 at 10:18 AM.
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