Originally Posted by **mdavies23** I have an exam coming up and I don't even know where to begin with this problem. Any help is appreciated
A teacher rides in an elevator that moves upwards at a constant velocity and holds a set keys 1.00m above the
floor of the elevator. After 2.00 seconds of moving upwards from the ground level of the science building, the
teacher releases the keys from their hand. Relative to the ground level of the building, he keys strike the floor of the
elevator at the exact height as where they were released.
(a) [7 pts] Qualitatively sketch, on the same graph, the vertical position (height) of both the keys and the elevator
as a function of time starting from the ground level until some time after the keys hit the floor. Indicate which
curve corresponds to the elevator and which corresponds to the keys. Label the point when the keys are
released.
(b) [4 pts] Describe the motion of the keys and the motion of the elevator shown in your position (height) vs. time
graph in part (a).
(c) [8 pts] Calculate the velocity of the elevator.
(d) [6 pts] Now consider the elevator as traveling downwards at the same constant speed found in part (c). The
keys are again released 1.00m above the floor of the elevator. What is the difference in height (relative to
ground level) between where the keys are released and where they hit the floor of the elevator?
(e) Bonus: [5 pts] Sketch the vertical position (height) of both the keys and the elevator as a function of time
during the downward motion described |

What needs to be noticed that due to the constant speed of both keys and elevator, relative gravity force on keys over the elevator remains sand as they were not moving.

Let us know whether you can proceed with the given solution (graph) by member above.

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