Go Back   Physics Help Forum > High School and Pre-University Physics Help > Kinematics and Dynamics

Kinematics and Dynamics Kinematics and Dynamics Physics Help Forum

Closed Thread
 
LinkBack Thread Tools Display Modes
Old Jun 1st 2008, 11:03 AM   #1
Junior Member
 
Join Date: Jun 2008
Posts: 2
Physics homework

I attached the file, its 4 questions , easy (its a pdf file) but i have 4 other

exams and i dont have much time to solve it, please someone help, i am

bad at physics, and i need help, thank u.
Attached Thumbnails
Physics homework-homework-ch10.pdf  
dragonpower is offline  
Old Jun 1st 2008, 11:07 AM   #2
Forum Admin
 
topsquark's Avatar
 
Join Date: Apr 2008
Location: On the dance floor, baby!
Posts: 2,356
Problem 1.

a) What is the definition of average angular acceleration?

b) The instantaneous angular acceleration is the slope of the curve at a given time. Your "curve" in this case is a straight line. How do you determine the slope of a line?

c) The angular displacement may be found from the time - angular velocity graph as the area under the curve for a given time limit.

d) You know the angular displacement from c). How do you convert an angle in radians to a number of revolutions?

-Dan
__________________
Do not meddle in the affairs of dragons for you are crunchy and taste good with ketchup.

See the forum rules here.
topsquark is offline  
Old Jun 1st 2008, 11:11 AM   #3
Forum Admin
 
topsquark's Avatar
 
Join Date: Apr 2008
Location: On the dance floor, baby!
Posts: 2,356
Problem 2.

I need some clarification on the angular displacement formula. Is it supposed to be $\displaystyle \theta = 3 - 2t$ or $\displaystyle \theta = 3 - 2t^3$?

In either case
a) The average angular acceleration is given by
$\displaystyle \bar{\alpha} = \frac{\omega - \omega_0}{t}$

How do you find the angular velocity if you know the angular displacement?

b) The angular acceleration here (without the word "average") means the instantaneous angular acceleration. How do you find the angular acceleration from the angular velocity you used in part a)?

I'll help out with the rest later. Give these two a try and if you still have questions about them, go ahead and post.

-Dan
__________________
Do not meddle in the affairs of dragons for you are crunchy and taste good with ketchup.

See the forum rules here.
topsquark is offline  
Old Jun 1st 2008, 01:50 PM   #4
Junior Member
 
Join Date: Jun 2008
Posts: 2
Well its  = 3 - 2t

its
=
3 - 2t

Yeah thanks but i still dont get in it , i just want the formulas and the solutions so i can hand it in, im weak at physics so im focusing on my other subjects. this is a homework that i need to hand in.

but thanks anyway
dragonpower is offline  
Old Jun 1st 2008, 04:34 PM   #5
Forum Admin
 
topsquark's Avatar
 
Join Date: Apr 2008
Location: On the dance floor, baby!
Posts: 2,356
Originally Posted by dragonpower View Post
its
=
3 - 2t

Yeah thanks but i still dont get in it , i just want the formulas and the solutions so i can hand it in, im weak at physics so im focusing on my other subjects. this is a homework that i need to hand in.

but thanks anyway
Do I even need to make my next comment then?

-Dan
__________________
Do not meddle in the affairs of dragons for you are crunchy and taste good with ketchup.

See the forum rules here.
topsquark is offline  
Closed Thread

  Physics Help Forum > High School and Pre-University Physics Help > Kinematics and Dynamics

Tags
homework, physics



Thread Tools
Display Modes


Similar Physics Forum Discussions
Thread Thread Starter Forum Replies Last Post
Physics Homework Problem. m1cojakle Electricity and Magnetism 1 Jun 22nd 2011 12:03 PM
College Homework Help, Statistics Homework Help, Finance Homework Help, Accounting Ho marklee Energy and Work 0 Jan 19th 2010 01:23 AM
Physics Liquids - Homework Help avramova Thermodynamics and Fluid Mechanics 3 Dec 31st 2009 04:39 AM
Physics Homework Question?? KaylaN Kinematics and Dynamics 1 Sep 2nd 2009 11:43 PM
Physics Homework Eli_09 Advanced Electricity and Magnetism 1 Feb 6th 2009 08:44 AM


Facebook Twitter Google+ RSS Feed