Physics Help Forum Man in a rotating spaceship

 Kinematics and Dynamics Kinematics and Dynamics Physics Help Forum

 Jul 11th 2017, 12:19 PM #1 Junior Member   Join Date: Jul 2017 Posts: 8 Man in a rotating spaceship A spaceman, who weighs 75 kg on the Earth, is in a room of a spaceship that is rotating around the axis through the centre of the spaceship with angular speed $\displaystyle \omega = 0,5 rad/s$. The spaceman is on a weight scale and he sees that he weighs 70 kg. At what distance he is from the axe of rotation? How can I deal with this problem? I don't know what formula use!
 Jul 11th 2017, 01:41 PM #2 Physics Team     Join Date: Jun 2010 Location: Morristown, NJ USA Posts: 2,272 Basic formula (as often the case) is: $\displaystyle F = m a$ For a rotating frame with constant angular velocity the value of acceleration is $\displaystyle a =r \omega^2$. You have values for m, F, and $\displaystyle \omega$, so you should be able to solve for r.
 Jul 12th 2017, 03:59 AM #3 Junior Member   Join Date: Jul 2017 Posts: 8 Thank you!

 Tags man, rotating, spaceship