Originally Posted by **SeanChrisXIV** Problem: A jet takes off from airport A and flies to airport B. The distance between the airports is 571.1 miles(903). After a 1.00hr layover, the jet returns to airport A. The total time for the round trip (including layover) is 3.50hr. The southbound trip from airport B to airport A takes 20.0min more than the northbound trip from airport A to airport B.
A) calculate the time required for each leg of the trip and the average velocity for each leg of the trip. |

Let $\displaystyle t_{AB}$ be the time to fly from A to B, and let $\displaystyle t_{BA}$ be the time to fly from B to A. Calling T the total trip time we have:

$\displaystyle T = 3.50 = t_{AB} + 1 + t_{BA}$

We also know that $\displaystyle t_{BA} = t_{AB} + 1/3$. (The 1/3 is 20 minutes in terms of hours.)

We now have two equations in two variables. Putting the equation for $\displaystyle t_{BA}$ (the second equation) into the first equation gives $\displaystyle 3.5 = t_{AB} + 1 + (t_{AB} + 1/3)$.

Can you go from there? If you can then see if you can finish the whole thing.

-Dan