A resovoir releases water into a 200 meter long pipe with 2m diameter.

At 5 degrees relative to x axis so the drop is 200m (sin 5 deg) = 17.4m

Since v o is 0 all I can solve for in this veolcity vector: v =(vx^2 + vy^2)^1/2

is for vy = (2gh)^1/2 = 18.4m/sec. Without vx how to solve for vz ?

Assume pipe is full.

http://www.calctool.org/CALC/eng/civil/hazen-williams_g
This format shows a velocity of aboiut 20msec. I am more interested in the

solution formula

Edit : The acceleration = g sine 5 degrees and

v^2 = 2(a*s) So v = (2*sin 5 deg * 9.8m/s^2*200m) ^1/2

=18.5m/s