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Old Jun 9th 2015, 10:29 AM   #1
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rotation

a ball rolls without slipping.The radius of gyration of the ball about an axis passing through the centre of mass is K.If radius of the ball be R,then the fraction of total energy assosciated with its rotational energy will be?
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Old Jun 9th 2015, 10:47 AM   #2
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What have you worked out so far?

What sort(s) of energy does the ball possess, assuming it rolls on a horizontal surface (which you should have mentioned).
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Old Jun 9th 2015, 11:01 AM   #3
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the answer comes as k^2 divided by k^2+R^2. how?
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Old Jun 9th 2015, 11:04 AM   #4
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I didn't ask for the answer and I am not going to do your homework for you.

But I did ask what should be a helpful question.
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Old Jun 9th 2015, 11:08 AM   #5
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the ball possess rotational and translational energy because it is in a rolling motion.Question seems confusing to me..
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Old Jun 9th 2015, 11:10 AM   #6
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Correct, so the link is the rotational speed which determines both the rotational energy and the translational velocity, which in turn determines the translational energy. And the mass will cancel out when you write the fraction to calculate the % or ratio.
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Old Jun 9th 2015, 11:13 AM   #7
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okay,thankyou!
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