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 Dec 19th 2013, 04:01 AM #2 Senior Member     Join Date: Apr 2008 Location: Bedford, England Posts: 668 Just a few quick pointers Q1 & Q8. Look up the "Combined Gas Law" on Wikipedia. Also from Wikipedia: The molar volume of an ideal gas at 100 kPa (1 bar) is 22.710 980(38) dm3/mol at 0 °C 24.789 598(42) dm3/mol at 25 °C The molar volume of an ideal gas at 1 atmosphere of pressure is 22.414 L/mol at 0 °C 24.465 L/mol at 25 °C Molar volume is the volume occupied my one mole of gas at the given conditions of pressure and temperature. 2.3 moles will thus take up 2.3 times as much volume, under the same conditions of temperature and pressure. Q2 & Q5. The buoyancy force is dependent on the mass of waste displaced, 0.53 m3 at 1000 kg/m3 =530 kg of water displaced. Force = mass * acceleration acceleration is due to gravity thus Force = 530 kg * 9.82 m/s2 Q3 The ratio of the forces is the same as the ratio of the areas. Sorry I haven't time at the moment, hopefully someone else will give you pointers for the rest.
 Dec 19th 2013, 10:37 AM #3 Senior Member     Join Date: Apr 2008 Location: Bedford, England Posts: 668 Ok, just one more Q10. The same volume of water per second has to go through the thin pipe as through the large pipe. Volume per second is given by (speed of flow) * (cross-section area of the pipe)
Dec 30th 2013, 08:42 PM   #4
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 Originally Posted by MBW Q10. The same volume of water per second has to go through the thin pipe as through the large pipe. Volume per second is given by (speed of flow) * (cross-section area of the pipe)
 The Helpers and the staff of the forum have agreed that they won't give a full answer to a problem posted with no attempt (except maybe in some cases). The Helpers are here to help you to understand your weaknesses by going through the asked questions with you and not here to solve your physics problems. It is imperative to show an attempt to a problem. If you don't know how to start, say it. Helpers will give you a push in the right direction. Welcome to the world of physics!
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 (m)No homework should be posted directly. Workings or any approaches to the questions should be shown to let others know you have made an effort or at least a try. It is to encourage people to learn but not to copy homework.
In this thread you didn't ask the OP to do any work at all. You did all the work for him! Were you not aware of the fact that no forum on the internet allows that to be done?

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