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Old Mar 14th 2009, 07:16 PM   #1
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Lightbulb Relative uncertainty

The radius of a sphere is measured with an uncertainty of 1%.
What is the percentage uncertainty in the volume?
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Old Mar 14th 2009, 11:09 PM   #2
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You should know the equation of volume of sphere is

$\displaystyle V=\frac{4\pi r^3}{3}$

Percentage error of volume
= (power of r )X( percentage error of r)
=3X1%
=3%
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