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Old Sep 18th 2019, 12:55 PM   #1
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Question Projectile Motion Problem with no Velocity given

Problem is Linked with a graphic I drew. Thanks!
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Old Sep 19th 2019, 02:06 AM   #2
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You start with the standard velocity acceleration displacement equation:

S=S0+V0t+1/2At^2

Where S is the height above the ground
and A is the acceleration due to gravity
t is time.

Then it a simultaneous equation situation:
you know A (=g=9.82 m/s/s)
you know two values for S (at the start and at the wall)

From this you should be able to work out V0
(note that this is just the vertical component, use some trigonometry to get the horizontal component).
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Last edited by Woody; Sep 19th 2019 at 02:09 AM.
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Old Sep 19th 2019, 03:59 PM   #3
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$\Delta x = v_0\cos{\theta_0} \cdot t \implies t = \dfrac{\Delta x}{v_0\cos{\theta_0}}$

$\Delta y = v_0\sin{\theta_0} \cdot t - \dfrac{1}{2}gt^2$

eliminate the parameter, $t$

$\Delta y = \Delta x \tan{\theta_0} - \dfrac{g \cdot \Delta x^2}{2v_0^2 \cos^2{\theta_0}}$

evaluate where necessary & substitute the given values and solve for $v_0$
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