Physics Help Forum Projectile Motion Problem with no Velocity given

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 Sep 18th 2019, 12:55 PM #1 Junior Member   Join Date: Sep 2019 Posts: 1 Projectile Motion Problem with no Velocity given Problem is Linked with a graphic I drew. Thanks! Attached Thumbnails
 Sep 19th 2019, 02:06 AM #2 Senior Member     Join Date: Jun 2016 Location: England Posts: 1,060 You start with the standard velocity acceleration displacement equation: S=S0+V0t+1/2At^2 Where S is the height above the ground and A is the acceleration due to gravity t is time. Then it a simultaneous equation situation: you know A (=g=9.82 m/s/s) you know two values for S (at the start and at the wall) From this you should be able to work out V0 (note that this is just the vertical component, use some trigonometry to get the horizontal component). topsquark likes this. __________________ ~\o/~ Last edited by Woody; Sep 19th 2019 at 02:09 AM.
 Sep 19th 2019, 03:59 PM #3 Junior Member     Join Date: Jan 2019 Posts: 25 $\Delta x = v_0\cos{\theta_0} \cdot t \implies t = \dfrac{\Delta x}{v_0\cos{\theta_0}}$ $\Delta y = v_0\sin{\theta_0} \cdot t - \dfrac{1}{2}gt^2$ eliminate the parameter, $t$ $\Delta y = \Delta x \tan{\theta_0} - \dfrac{g \cdot \Delta x^2}{2v_0^2 \cos^2{\theta_0}}$ evaluate where necessary & substitute the given values and solve for $v_0$ topsquark likes this.

 Tags motion, problem, projectile, velocity

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