Physics Help Forum Need help with calculus problem

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 Nov 6th 2018, 10:42 AM #1 Junior Member   Join Date: Nov 2018 Posts: 1 Need help with calculus problem Solved zz31 likes this. Last edited by strawberry; Nov 6th 2018 at 02:45 PM.
Nov 6th 2018, 10:56 AM   #2
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 Originally Posted by strawberry If the position of a uniformly accelerating object is given by 4t^2+7t+1 what would be the velocity of the object when time is at 5.0 seconds? Helppp, what do I do?
If you know the position and the secs than the velocity depends on when it started at or, any time. I did skip the math you wrote. Was that in there?

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Nov 6th 2018, 11:12 AM   #3
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Reminds me of when I wanted to draw the curvature of space around the earth. I mean exactly, as it spreads out. I was figuring it out by the acceleration due to gravity, 9.8, or 10m/s^. I was going to put it on a graph or chart. Frame it like a piece of art. Simple frame. Maybe behind glass. I stared with:
9.8m/s/s = acc.

0 sec, 0 m, 0 m/s; 9.8/m/^
1 sec, m. M/s
2 sec, m, m/s
3s, m, s

I would of displayed that in the ledgen in vertical rectangle in the upper left of the artwork. Then the graphic of the curvature of space around a sphere (planet earth).
I could of plotted out my drawing on AutoCad, and pasted in the ledgen of that data, from excel. Maybe another software to hold the two like paint.
 Originally Posted by zz31 If you know the position and the secs than the velocity depends on when it started at or, any time. I did skip the math you wrote. Was that in there? Sent from my LG-M210 using Tapatalk
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Nov 6th 2018, 01:45 PM   #4
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 Originally Posted by strawberry If the position of a uniformly accelerating object is given by 4t^2+7t+1 what would be the velocity of the object when time is at 5.0 seconds? Helppp, what do I do?
Velocity is defined as the change in position per unit time, or in other words the slope of the position versus time graph. I don't know what your level of math capability is, but if you know how to determine the time derivative of a function, then:

$v(t) = \frac {dx}{dt}$

Nov 6th 2018, 02:10 PM   #5
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 Originally Posted by zz31 Reminds me of when I wanted to draw the curvature of space around the earth. I mean exactly, as it spreads out. I was figuring it out by the acceleration due to gravity, 9.8, or 10m/s^. I was going to put it on a graph or chart. Frame it like a piece of art. Simple frame. Maybe behind glass. I stared with: 9.8m/s/s = acc. 0 sec, 0 m, 0 m/s; 9.8/m/^ 1 sec, m. M/s 2 sec, m, m/s 3s, m, s I would of displayed that in the ledgen in vertical rectangle in the upper left of the artwork. Then the graphic of the curvature of space around a sphere (planet earth). I could of plotted out my drawing on AutoCad, and pasted in the ledgen of that data, from excel. Maybe another software to hold the two like paint. Sent from my LG-M210 using Tapatalk
If you don't know a time to use either when you started or at any point from the 5 sec. Any answer you get is going to a math equation. The math equation will then just be a different equation for figuring out the velocity. Just like the acceleration equation. You don't need any level of math.