Sep 18th 2018, 10:21 AM
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#1 |
Junior Member
Join Date: Oct 2017
Posts: 8
| 2 blocks on top of each other exerting pressure on the ground
So the question is that there are 2 blocks on top of each other of different mass (M1 and M2) and different cross sectional areas (A1 and A2). They are lying on a smooth surface. What would be the pressure exerted by the blocks on the surface.
a) (M1g/A1) +(M2g/A2)
b) (M1g/A1) +(M2g/A1)
c) (M1g/A2) + (M2g/A2)
d) (M1g/A1) - (M2g/A2)
There is no answer given. However, I'm bit confused why there is no option of ((M1+M2)*g)/(A1+A2). Since Fg = Fn and P = Fn/A, the normal force of the blocks would be (M1+M2)*g. That would be divided by the sum of the areas. How would I solve this?
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