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Old Jan 10th 2018, 05:23 PM   #1
cxz
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Cancel reaction force

This triangular moves along the x axes. It is in equilibrium as the spring force Fx=100N from the right is canceled by the reaction on the wall.
A roller which moves only along the y axes applies force Fy.
Angle θ=25 degrees. No friction, no gravity.

How much force Fy is needed in order to cancel the reaction on the wall?

Could I say that Fy*sin25=100--->Fy=100/sin25=236N?
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Cancel reaction force-20180110_213306.jpg   Cancel reaction force-20180111_141150.jpg  

Last edited by cxz; Jan 11th 2018 at 06:26 AM.
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Old Jan 10th 2018, 09:25 PM   #2
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Yes ... that looks correct to me.
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Old Jan 11th 2018, 06:27 AM   #3
cxz
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I think I have made a mistake. There must be an Fx and an Fy reaction to the 100N
Please see my new picture above.
Could you please check my new calculations?
Thanks
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Old Jan 11th 2018, 03:05 PM   #4
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No ...I think you were right the first time ...

The question says the triangle is in equilibrium . the force from the spring is 100N , so this is the horizontal component of Fy

so Fy sin 25 =100

You don't need to be concerned about the vertical component felt by the triangle from Fy ... it will always be balanced by the two rollers pushing up.

Last edited by oz93666; Jan 11th 2018 at 03:12 PM.
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