Physics Help Forum Integration Problem
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 Feb 6th 2009, 03:44 PM #1 Junior Member     Join Date: Nov 2008 Posts: 12 Integration Problem How do integrate the indefinite integral: (x^2-3x-5)/(x+1) dx Thanks
 Feb 6th 2009, 09:13 PM #2 Senior Member   Join Date: Dec 2008 Location: Las Cruces NM Posts: 256 Divide $\displaystyle x+ 1$ into $\displaystyle x^2 -3x -5$ obtaining the quotient $\displaystyle x- 4$ and the remainder $\displaystyle 1$. So $\displaystyle \frac {x^2 -3x - 5} {x + 1} = (x+1)(x-4) + \frac {1}{x+1}$ Then Integrate the polynomial and the fraction separately.

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