Have you made any attempt on this yourself?
As Otto is pulling away with a constant acceleration of 1.07 m/s/s

Since the bus starts with speed 0, its speed after t seconds is 1.07t m/s. Taking the position of the busstop to be x= 0, the busses position after t seconds is x= 0.535t^2.
Lisa is still 11.0 meters away

So Lisa's initial position (assuming the bus is moving
away from her rather than toward her) is y(0)= 11.0.
running at her top constant speed of 5.01 m/s.

So her position, relative to the but stop, after t seconds is y(t)= 5.01t 11.0.
When will Lias catch the bus?

She will catch the bus when her position is the same as the position of the bus:
x= y or 0.535t^2= 5.01t 11.0. Solve 0.535t^2 5.01t+ 11.0= 0. The quadratic formula is probably the simplest method.
Where will Lisa catch the bus?

Set t equal to the value you just got in either of the x and y equations above.