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Old Jul 2nd 2014, 02:00 AM   #1
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What happens to your weight

Need help to understand Physics basic concepts

Suppose a planet is shrinking to is one-tenth of its original diameter without change in its mass and you are standing on the surface of that planet. What happens to your weight? it would be more or less?

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Old Jul 2nd 2014, 04:38 AM   #2
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If you apply Newton's Law of Gravity you should be able to see what happens:

F=GMm/r^2

where G is the gravitational constant, M the mass of the planet, m is your mass, and r is the distance between the two center of masses (effectively the radius of the planet). In your scenario G, M, and m are all constant, but r becomes r/10. So what happens to the force of gravity acting on you (i.e., your "weight")?
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Old Jul 3rd 2014, 02:15 AM   #3
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Originally Posted by ChipB View Post
If you apply Newton's Law of Gravity you should be able to see what happens:

F=GMm/r^2

where G is the gravitational constant, M the mass of the planet, m is your mass, and r is the distance between the two center of masses (effectively the radius of the planet). In your scenario G, M, and m are all constant, but r becomes r/10. So what happens to the force of gravity acting on you (i.e., your "weight")?
Thank you so much for your nice and simple explanation!!!
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