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Old Nov 7th 2018, 11:42 AM   #1
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Join Date: Oct 2018
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Equilibrium

Iím having trouble understanding this question.

A rigid uniform beam (0.5m in length) of weight 200N is hinged to a wall and held horizontally by a string 40 degrees to the horizontal. a) Calculate the tension in the string. b) The horizontal contact force of the wall on the hinge.

Iím assuming I have to use moments?

I think the weight would provide a clockwise moment
m = Fs
= 200N x 0.25 (because I think the weight will act in the centre of the beam?)

This will equal the anti-clockwise moment provides by the tension in the string.
For this would I work out the vertical component? Iím lost on what I have to do to be honest, any help would be appreciated.
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Old Nov 7th 2018, 02:14 PM   #2
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Yes, since the beam is uniform we can treat the weight as concentrated at the center. We are told that the beam is held at 40 degrees to the horizontal so the horizontal component of weight is 200 N times cos(40) and the vertical component is 200 N times sin(40).
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