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 Sep 1st 2018, 08:34 AM #1 Junior Member   Join Date: Jan 2018 Posts: 5 Support reactions Hello, I have had the following question: Determine the two support reactions at positions ‘A’ and ‘B’ for the following simply supported beam which is acted on by a uniformly distributed load (UDL) and two point loads. UDL = 1.2K/n 6Kn 3Kn A------------- ------------------- -----------B 2.1m 1.05m 1.05 I have answered it: (6 x 2.1) + (3 x 3.15) =R2 x 4.2m (6 x 2.1) + (3 x 3.15) / 4.2 = R2 12.6 + 9.45 / 4.2 = R2 22.05 / 4.2m = R2 5.25kN = R2 R1 9 – 5.25 = 3.75kN R1= 3.75kN R2= 5.25kN Is this correct? Im not sure! Thanks Dave
 Sep 1st 2018, 12:23 PM #2 Senior Member   Join Date: Apr 2015 Location: Somerset, England Posts: 1,009 I am not clear as to the length of your beam or the positions of the point loads or how far along the beam the UDL extends. But let's try a simple check shall we? The sum of the vertical loads must equal the sum of the two vertical reactions. Why have you said R1 and R2 not Ra and Rb ? Be consistent with the question. (1.2*length of UDL + 6 +3 ) = (3.75 +5.25) If you are correct. It is clear you are not since this implies zero UDL. Please resubmit correctly shown. topsquark likes this.

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