Originally Posted by **electrogeek** So does 2 sin (theta) = 0.5 cos (theta) ? |

No.

$\displaystyle B_h \ \times \ 2 \sin \theta = W(2.5 \cos \theta -2)$

Maybe the attached will help you visualize this. Then use the fact that $\displaystyle B_h/B_v = \tan \theta$, so the $\displaystyle B_h$ on the left hand side can be replaced by $\displaystyle B_v \tan \theta = W \tan \theta$. Then it's a matter of some manipulation to solve for cos theta.