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Old Mar 1st 2018, 05:05 PM   #1
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Finding area of solar collector

Hi, I was wondering if someone could help me with this question:
The total electric generating capacity of Canada is 81GW. What is the area (in km^2) of horizontal photovoltaic solar collector that could satisfy this need? Note the average insolation on a horizontal surface is 4.8kWh/m^2 for a 24 hour period. Assume the solar cells have an efficiency of 19%
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Old Mar 1st 2018, 05:33 PM   #2
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I think the rules are here you're suppose to show some sort of attempt at the question ...

But I'll give you a bit of a push start ...

That 'isolation" figure .... Note it's in KWhrs .... that's a measure of Energy .... KW is a measure of Power ... I hope you understand the difference.

We are told "average insolation on a horizontal surface is 4.8kWh/m^2 for a 24 hour period" ... that means the Energy received for each square meter is 4.8 KWhrs over a 24 hr period ...

If the panel was 100% efficient you could run a 2Kw kettle for 2.4Hrs .... once a day, if the panel was 1 sq m. and laid horizontally.

Last edited by oz93666; Mar 1st 2018 at 05:36 PM.
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