Here is the question...

A parallel plate capacitor with paper between the plates has an electric field of

9.31 104 V/m between the plates. The plates are

1.75 mm apart and the charge on each plate is 0.775 µC. Find the capacitance of this capacitor.

1

F

Find the area of each plate.

2

m2

OKay, so the capacitance was easy to find, Q=CV, solve for C, however, I'm having a difficult time with the area of each plate.

Since we know the capacitance is 4.75e-9, we can use the equation for Capacitance to find area, right?

C= [(dielectric constant)x(8.85e-12)x(area)]/d

rearrange:

Area= (C x d)/[(dielectric constant)x8.85e-12]

The dielectric constant of paper should be between 1.5 and 3, as far as I have found out, but when I use either 1.5 or 3, it doesn't work.

Am I doing this right? What am I doing wrong here?

Thanks in advance!!