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Old Jul 23rd 2010, 10:19 PM   #1
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Join Date: Nov 2009
Posts: 7
Electrostatic force,electric field,electric potential,electric flux

Cube: 10 cm each side

Each q at the corner of the cube is +100 sc.

Find:

a) magnitude and direction of the electrostatic force at the center of the cube.
b) magnitude and direction of the electric field at the center of the cube of tq in place at this pt.
c) find the electric potential and work done if tq of 1000 sc is placed at the center of the cube.
d) what is the electric flux at the center of the cube.


My Solution:

a)

Sq1q9 = square root of (5 cm)^2+(5 cm)^2 = 7.07 cm
S29,S39,S49,S59,S69,S79,S89= 7.07 cm

Fq1q9=k[q1q9/(s19)^2 =1 dyne cm^2/sc^2[(100sc)(100sc)/(7.07cm)^2] = 200.08 dyne
Fq29,Fq39,Fq49,Fq59,Fq69,Fq79,Fq89= 200.08 dyne

x and y components

x axis

Fq19 = -200.08 dyne
Fq29 = 0
Fq39 = 200.08 dyne
Fq49 = 0
Fq59 = 0
Fq69 = 200.08 dyne
Fq79 = 0
Fq89 = -200.08 dyne

y axis


c. V= 1 dyne cm^2/sc^2(100/7.07)x8
V= 113.12 dyne. cm

d. Eq = 800 sc x 1 C/1x10^9 sc = 8x10^-7 C

electric flux = 8x10^-7 C/8.85x10^-12 C^2/Nm^2
electric flux = 90,395.48 Nm^2/C

I can't answer letter a and b because I don't know how will I draw the free bodied diagram of it. I attach a drawing so you can see where I place the charges. I hope you can help me thanks
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Electrostatic force,electric field,electric potential,electric flux-a3.jpg  
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